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Home/ Questions/Q 8363665
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T12:14:14+00:00 2026-06-09T12:14:14+00:00

I must be missing some fundamental concept of processing an XML document. Here is

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I must be missing some fundamental concept of processing an XML document. Here is my source XML:

<?xml version="1.0" encoding="ISO-8859-1"?>
<Root>
  <Element>visitorNameAlt</Element>
  <Element>visitorScore</Element>
  <Element>visitorTimeouts</Element>
  <Element>Blank</Element>
  <Element>homeNameAlt</Element>
  <Element>homeScore</Element>
  <Element>homeTimeouts</Element>
  <Element>Blank</Element>
  <Element>period</Element>
  <Element>optionalText</Element>
  <Element>flag</Element>
  <Element>Blank</Element>
  <Element>scoreLogo</Element>
  <Element>sponsorLogo</Element>
</Root>

And my XSL stylesheet:

<?xml version="1.0" encoding="ISO-8859-1"?>

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" indent="yes"/>

<xsl:template match="/">
    <xsl:for-each select="/Root">
        <xsl:value-of select="position()"/>
        <xsl:value-of select="Element"/>
    </xsl:for-each>
</xsl:template>

</xsl:stylesheet>

All I want is to pluck the “Element” names from the source XML doc with their relative position in front.

My output is just “1” followed by the first element and nothing more.

I am new to XSLT, but have processed other documents successfully with for-each.

Thanks in advance.

Bill

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T12:14:16+00:00Added an answer on June 9, 2026 at 12:14 pm

    You’re looping over Root tags, not Element tags. Try this:

    <xsl:template match="/">
      <xsl:for-each select="/Root/Element">
         <xsl:value-of select="position()"/>
         <xsl:value-of select="."/>
      </xsl:for-each>
    </xsl:template>
    

    Note that you must change the second value-of select to “.” or “text()”.

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