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Home/ Questions/Q 8293815
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T13:57:50+00:00 2026-06-08T13:57:50+00:00

I need a function to work for only the given object. I’m not sure

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I need a function to work for only the given object. I’m not sure if its possible, but I tried something like:

var a = {
    b: function(a) {
        return display(a)
    }
}
a.prototype.display = function(a) {
    return a;
}
alert(a.b('Hi'))​//This is suppose to work
alert(display(a))//This isn't suppose to work

This doesn’t work though, not sure why. I’m kinda new to prototype. I used it with String.prototype for example but all the other stuff I still need to learn. Thanks for the help.

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  1. Editorial Team
    Editorial Team
    2026-06-08T13:57:52+00:00Added an answer on June 8, 2026 at 1:57 pm

    You need a private method in your object. The only way to achieve this in javascript is to keep the function in closure and execute it in the context of current object.

    var a = (function () {
          var display = function (a) {
              return a;
          };
    
          return {
             b : function(a) {
                 // display exist in closure scope of b;
                 //executing display in the context of current object
                 return display.apply(this, arguments);
             }
          };
    })();
    

    Here display is not accessible outside.

    alert(a.b("hi")); //will return hi
    

    a.display("hi"); is not accessible.

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