Question

I need help figuring out one issue in my script, options ( c, e , d, f and g) are mandatory options in my script and they are always implied before running my script otherwise script wont be executed. Now i have added a command and if i tried to to execute my script without any necessary parameters, it’d be still be executed and exit out , my script shouldn’t be executing without passing any required parameters but it still does and exits out. how can i fix this?

Thank you in advance,

#!/bin/bash


cont=false


options=':c:d:e:f:g:h:i' # additional option characters go here
while getopts $options option
do
    case $option in
        c  ) cont=true;;
        d  ) hello="$OPTARG"
        e  ) hi="$OPTARG"
        f  ) Fri="$OPTARG"
        g  ) Sat="$OPTARG"
        h  ) SUN="$OPTARG"
        i  ) ....so on
        # more option processing can go here

    esac
done

shift $(($OPTIND - 1))

Answer 1

Using an array called mandatory that contains required options and setting the array element to - for given options, the code below reports an error for unspecified mandatory options:

mandatory=(c d e f g)
options=':c:d:e:f:g:h:i'
while getopts $options option
do
  for ((i = 0 ; i < ${#mandatory[@]} ; i++ )); do
    [[ $option == ${mandatory[$i]} ]] && mandatory[$i]="-"  
  done
  case $option in
      c  ) echo c; cont=true;;
      d  ) hello="$OPTARG";;
      e  ) hi="1"
  esac
done

for ((i = 0 ; i < ${#mandatory[@]} ; i++ )); do
  if [[ ${mandatory[$i]} != '-' ]]; then
    echo "option ${mandatory[$i]} was not given"
    exit 1
  fi
done

if cat /proc/mounts | grep /dev ; then echo "mount exists
   else
   echo "mount doesn't exist"
   exit ; 
fi