Question

I need help with the following code that requires me to:

• Declare 3 double type variables, each representing one of three sides of a triangle.

• Prompt the user to input a value for the first side, then

• Set the user’s input to the variable you created representing the first side of the triangle.

• Repeat the last 2 steps twice more, once for each of the remaining 2 sides of the triangle.

• Use a series of nested if / else statements to determine if the triangle having side-lengths as set by the user is an EQUILATERAL, ISOSCELES, or SCALENE triangle.
  [Note: look to the Wikipedia page on ‘triangle’ for definitions of these three types of triangles.]

• Print the resulting triangle type to the console.

• Ensure your Triangle detector works by running it 5 times as in the example above. You may use the same values as in the example.

I currently have:

//lab eleven program code on triangles
#include <iostream.h>

main()
{
    //variables
    float aside, bside, cside;
    //enter side a
    cout<<"enter the length of side a "<<endl;
    cin>>aside;
    //enter side b
    cout<<"enter the length of side b "<<endl;
    cin>>bside;     
    //enter side c
    cout<<"enter the length of side c "<<endl;
    cin>>cside;

// all sides equal
if(aside==bside && bside==cside)                 
   cout << "Equilateral triangle\n";

// at least 2 sides equal
else if(aside==bside || aside==cside || bside==cside)   

   cout << "Isosceles triangle\n";
// no sides equal
else                                
   cout << "Scalene triangle\n";            
}

But I need help with the if and else if statements to determine the type triangle. Our professor has not covered this topic in class.

We use the program Ch 6.3 on Windows.

Answer 1

if(a==b && b==c)                    // all sides equal
   cout << "Equilateral triangle\n";
else if(a==b || a==c || b==c)       // at least 2 sides equal
   cout << "Isosceles triangle\n";
else                                // no sides equal
   cout << "Scalene triangle\n";