Question

I need to call a function, in PHP, that accepts 3 parameters, RGB Values. This function converts RGB color values to HSL values, so (R,G,B) is needed in the parenthesis.

This is my function:

function RGBtoHSL($red, $green, $blue) {
  // convert colors
}

Which, if I make a test call of the following, it works just fine:

RGBtoHSL(255,0,0);

and also works like this:

RGBtoHSL(255,000,000);

Now, further down my page I have a variable $displayRGB which holds the current pixels RGB values in this format xxx,xxx,xxx. I’ve echoed this variable to test the format matches my requirements and it does, but when I try and add this variable to my function caller, it fails with the error “Missing argument 2, Missing argument 3” and points to this line:

RGBtoHSL($displayRGB);

I’m still teething in PHP (come from ASP), can somebody please help point me in the right direction and pass me my dummy?

Answer 1

You can’t pass in an array (I assume $displayRGB is an array) as “all three arguments” in PHP. Try

RGBtoHSL($displayRGB[0], $displayRGB[1], $displayRGB[2]);

or modify your function to accept an array.

If $displayRGB is a string of “xxx,yyy,zzz” you can run an explode on it

$colors = explode(",", $displayRGB);

and it will set $colors as an array with indices containing xxx, yyy and zzz.

Then pass it as I mentioned above.