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Home/ Questions/Q 8320221
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T22:35:06+00:00 2026-06-08T22:35:06+00:00

I need to read in a php template file in a bash script, then

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I need to read in a php template file in a bash script, then replace some variables in the template (can be anything, like $(variable)), and finally output the whole content to a new file.

I originally had

stuff=$stuff bash templatefile > newfile

for non-PHP files

cat <<END
//stuff
END

But my php template file looks something like

#!/usr/bin/php
<?php
//lots of php variables, so can't use bash variables that have the same $ prefix
?>

Because PHP also uses the $ prefix for its variables like bash, I can’t easily pass in parameters. How would I go about it?

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  1. Editorial Team
    Editorial Team
    2026-06-08T22:35:08+00:00Added an answer on June 8, 2026 at 10:35 pm

    Try this answer:
    Bash Templating: How to build configuration files from templates with Bash?

    This allows you to use ${varname} instead of $varname

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