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Home/ Questions/Q 8286075
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T11:37:21+00:00 2026-06-08T11:37:21+00:00

I need to write a method like this: -(void)doStuff:(int)options; Based in the a typedef

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I need to write a method like this:

-(void)doStuff:(int)options;

Based in the a typedef enum like this:

typedef enum
{
    FirstOption,
    SecondOption,
    ThirdOption
} MyOptions

What I need to to do in order to be able to call the method in this way (i.e. calling the method with more than one option “enabled”:

[self doStuff:(FirstOption | ThirdOption)];

Do I need to setup the typedef enum differently? And how I check the options received in the method, a simple if (options == ...)?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T11:37:23+00:00Added an answer on June 8, 2026 at 11:37 am

    What you call for is a bit array. Define your options like this:

    enum MyOptions
    {
        FirstOption = 0x01, // first bit
        SecondOption = 0x02, // second bit
        ThirdOption = 0x04, // third bit
        ... = 0x08 ...
    };
    

    Combine the options like you suggested, with |, and test for them with & (options & SecondOption).

    - (void) doStuff: (MyOptions) options
    {
        if ( options & FirstOption )
        {
            // do something fancy
        }
    
        if ( options & SecondOption )
        {
            // do something awesome
        }
    
        if ( (options & SecondOption) && ( options & ThirdOption) )
        {
            // do something sublime
        }
    }
    
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