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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T15:47:12+00:00 2026-05-22T15:47:12+00:00

I read that the first 3 GBs are reserved for the process and the

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I read that the first 3 GBs are reserved for the process and the last GB is for the Kernel. I also read that the kernel is loaded starting from the 2nd MB of the physical address space (depending on the configuration). My question is that is the mapping of that last 1 GB is same for all processes and maps to this physical area of memory?

Another question is, when a process switches to kernel mode (eg, when a sys call occurs), then what page tables are used, the process page tables or the kernel page tables? If kernel page tables are used, then they can’t access the memory locations belonging to the process. If that is the case, then there is apparently no use for the kernel virtual memory since all access to kernel code and data will be through the mapping of the last 1 GB of process address space. Please help me clarify this (any useful links will be much appreciated)

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  1. Editorial Team
    Editorial Team
    2026-05-22T15:47:12+00:00Added an answer on May 22, 2026 at 3:47 pm

    Yes, the mapping of the kernel part of the address space is the same in all processes. Part of it does map that part of the physical memory where the kernel image is loaded, but that’s not the bulk of it – the remainder is used to map other physical memory locations for the kernel’s runtime working set.

    When a process switches to kernel mode, the page tables are not changed. The kernel part of the address space simply becomes accessible because the CPL (Current Privilege Level) is now zero.

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