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Home/ Questions/Q 8250997
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T00:05:44+00:00 2026-06-08T00:05:44+00:00

I read the documentation on this, and I’m not totally clear. I’ve zeroed in

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I read the documentation on this, and I’m not totally clear. I’ve zeroed in on the set method and I’m thinking that I would do reordering like this:

list.set(0,myObj);//Move first
list.set(list.indexOf(myObj) - 1, myObj);//Move up
list.set(list.indexOf(myObj) + 1, myObj);//Move down
list.set(list.size() - 1, myObj);//Move last

The documentation at http://developer.android.com/reference/java/util/List.html states that set returns the object that is displaced. So that leads me to think that I then have to re-place that object. Am I correct? So after a set operation as I described I would have two references to the object in the list. This would mean I’d have to loop down the list to place all the other object appropriately?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T00:05:46+00:00Added an answer on June 8, 2026 at 12:05 am

    Look at Collections class to make things like reverse, reorder, sort etc.
    You’re looking probably for rotate or swap.

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