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Home/ Questions/Q 304945
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T07:19:39+00:00 2026-05-12T07:19:39+00:00

I rotate my image with: UIImage *image = [UIImage imageNamed:@doneBtn.png]; CGImageRef imgRef = image.CGImage;

  • 0

I rotate my image with:

UIImage *image = [UIImage imageNamed:@"doneBtn.png"];
CGImageRef imgRef = image.CGImage;

CGFloat width = CGImageGetWidth(imgRef);
CGFloat height = CGImageGetHeight(imgRef);

CGAffineTransform transform = CGAffineTransformIdentity;
CGRect bounds = CGRectMake(0, 0, width, height);
transform = CGAffineTransformRotate(transform, degreesToRadians(10));

UIGraphicsBeginImageContext(bounds.size);
CGContextRef context = UIGraphicsGetCurrentContext();
CGContextConcatCTM(context, transform);

CGContextDrawImage(UIGraphicsGetCurrentContext(), CGRectMake(0,0,width,height), imgRef);
UIImage *imageCopy = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();

img.image=imageCopy;

When I display the image, I see it under my 10 degree but the image is cut off on the edges.

Does somebody know how to fix this? Here’s an image for clarification.

alt text http://img197.imageshack.us/img197/7077/problemkfr.png

I have been trying all day yesterday, but can’t figure it out.

Another example image:

alt text http://img25.imageshack.us/img25/3370/afbeelding6b.png

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  1. Editorial Team
    Editorial Team
    2026-05-12T07:19:39+00:00Added an answer on May 12, 2026 at 7:19 am

    I solved it now, i have to change the width/height value of bounds and
    the x/y in CGContextDrawImage

    CGRect bounds = CGRectMake(0, 0, width+10, height+10);
    CGContextDrawImage(UIGraphicsGetCurrentContext(), CGRectMake(10,0,width,height), imgRef);
    
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