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Home/ Questions/Q 8322391
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T23:22:31+00:00 2026-06-08T23:22:31+00:00

I started to use OpenGeoDB to find the zip code and the city name.

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I started to use OpenGeoDB to find the zip code and the city name. My MySQL query reads like this:

SELECT      `d`.`text_val` AS `city`, (
    SELECT  `text_val`
    FROM    `geodb_textdata`
    WHERE   `loc_id` = ANY (
        SELECT  `loc_id`
        FROM    `geodb_textdata`
        WHERE   `text_val` LIKE '08%'
    )
        AND `text_type` = '500300000'
) AS `plz`, `c`.`lat`, `c`.`lon`
FROM        `geodb_textdata`    AS  `d`
LEFT JOIN   `geodb_coordinates` AS  `c` USING   (`loc_id`)
WHERE       `loc_id` = ANY (
    SELECT  `loc_id`
    FROM    `geodb_textdata`
    WHERE   `text_val` LIKE '08%'
)
    AND `text_type` = '500100000'

If I run this query with a full zip code or city name it works great, but with the code above, I get the error code

#1242 - Subquery returns more than 1 row

I was using Google and I found, that I should use ANY between the = and the subquery. Do you have any idea how I could fix my code? Thank you in advance. 🙂

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T23:22:32+00:00Added an answer on June 8, 2026 at 11:22 pm

    I suspect that this subquery is returning more than 1 row:

    (
    SELECT  `text_val`
    FROM    `geodb_textdata`
    WHERE   `loc_id` = ANY (
        SELECT  `loc_id`
        FROM    `geodb_textdata`
        WHERE   `text_val` LIKE '08%'
    )
        AND `text_type` = '500300000'
    ) AS `plz`
    

    Update: Untested, but give this query a try.

    SELECT      `d`.`text_val` AS `city`, `d2`.`text_val` AS `plz`, `c`.`lat`, `c`.`lon`
    FROM        `geodb_textdata`    AS  `d`
    LEFT JOIN  `geodb_textdata`    AS  `d2` USING (`loc_id`)
    LEFT JOIN   `geodb_coordinates` AS  `c` USING   (`loc_id`)
    WHERE       `d`.`text_val` LIKE '08%' AND `d`.`text_type` = '500100000'
    AND         `d2`.`text_val` LIKE '08%' AND `d2`.`text_type` = '500300000'
    
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