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Home/ Questions/Q 1094521
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T23:59:02+00:00 2026-05-16T23:59:02+00:00

I tried to implement a simple yes/no input with java.util.Scanner. My code looks like

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I tried to implement a simple yes/no input with java.util.Scanner. My code looks like this:

public boolean ask(String quest){
  String answ = scann(quest + " (y/n)");
  answ = answ.split("")[1].toLowerCase();
  if(answ == "y") { return true; }
  if(answ == "n") { return false;}

  //if answer isnt understood
  printOut("Please enter 'y' or 'n'! Answered: " + answ +"!");
  return ask(quest);
}

To make it short: It ends up with an infinite request for the answer. The answer is never understood, I got no clue what I did wrong.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T23:59:02+00:00Added an answer on May 16, 2026 at 11:59 pm

    You cannot use == to compare strings in Java (well, you can, but it’s not the right way to compare their literal values). You need to use equals():

      if ("y".equals(answ)) { return true; }
      if ("n".equals(answ)) { return false; }
    
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