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Home/ Questions/Q 6219183
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T07:44:08+00:00 2026-05-24T07:44:08+00:00

I try to use XMLHttpRequest() to post data to a url. I wrote the

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I try to use XMLHttpRequest() to post data to a url.
I wrote the following javascript:

function makePostRequest(url, params) {
var httpRequest = new XMLHttpRequest();
httpRequest.open("POST", url, true);
//Send the proper header information along with the request
httpRequest.setRequestHeader("Content-type", "application/json");

httpRequest.onreadystatechange = function() {//Call a function when the state changes.
    if(httpRequest.readyState == 4 && httpRequest.status == 200) {
        alert(httpRequest.responseText);
    }
}
httpRequest.send(params);}

then i need to pass two php variables into this function in php file, one is a url, another is json data to be posted.

$url = "http://www.hello.com";
$json_str = "{\"format\": \"json\",
          \"event\": \"revert\",
      \"api_key\": \"$wgAPIKey\"}";

$editpage->editFormTextTop = 
          "<input type='button'value='hello' onclick='makePostRequest(\"$url\", \"$json_str\")' />";

After execution, i got the following error from firebug:

missing ) after argument list
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T07:44:08+00:00Added an answer on May 24, 2026 at 7:44 am

    Here is what I suggest. To clean up the code, let’s removed the embedded onclick and give it an ID:

    $editpage->editFormTextTop = "<input type='button' id="requestBtn" />";
    

    Now in the head of your script you can initialize the values;

    Note: This code is simplified

    <script>
    window.onload = function() {
       var url = "http://www.hello.com";
       var jsonString = "{\"format\": \"json\",\"event\": \"revert\",\"api_key\": \"<?php echo $wgAPIKey ?>\"}";
       // now we can assign the function to the button
       document.getElementById("requestBtn").onclick = function () {
          makePostRequest(url,json_string);
       }
    }
    </script>
    
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