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I understand from here that the name of an array is the address of the first element in the array, so this makes sense to me:
int nbrs[] = {1,2};
cout << nbrs << endl; // Outputs: 0x28ac60
However, why is the entire C-string returned here and not the address of ltrs?
char ltrs[] = "foo";
cout << ltrs << endl; // Outputs: foo
Because iostreams have an overload for
char *that prints out what the pointer refers to, up to the first byte that contains a\0.If you want to print out the address, cast to
void *first.