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Home/ Questions/Q 8343421
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T06:03:21+00:00 2026-06-09T06:03:21+00:00

I use the following function to create instances of functions in JavaScript from an

  • 0

I use the following function to create instances of functions in JavaScript from an array of arguments:

var instantiate = function (instantiate) {
    return function (constructor, args, prototype) {
        "use strict";

        if (prototype) {
            var proto = constructor.prototype;
            constructor.prototype = prototype;
        }

        var instance = instantiate(constructor, args);
        if (proto) constructor.prototype = proto;
        return instance;
    };
}(Function.prototype.apply.bind(function () {
    var args = Array.prototype.slice.call(arguments);
    var constructor = Function.prototype.bind.apply(this, [null].concat(args));
    return new constructor;
}));

Using the above function you can create instances as follows (see the fiddle):

var f = instantiate(F, [], G.prototype);

alert(f instanceof F); // false
alert(f instanceof G); // true

f.alert(); // F

function F() {
    this.alert = function () {
        alert("F");
    };
}

function G() {
    this.alert = function () {
        alert("G");
    };
}

The above code works for user built constructors like F. However it doesn’t work for native constructors like Array for obvious security reasons. You may always create an array and then change its __proto__ property but I am using this code in Rhino so it won’t work there. Is there any other way to achieve the same result in JavaScript?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T06:03:23+00:00Added an answer on June 9, 2026 at 6:03 am

    You can’t fully subclass an array.

    However, you can use Object.create to remove a lot of complexity from your current code (ex).

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