Question

I use this code to get referer url:

<?php echo $_SERVER['HTTP_REFERER']; ?>

And the output is:

http://example.com/application/view/viewleave.php?idleave=1

How should i do to get this?

http://example.com/application/view/viewleave.php

Answer 1

You could lop off everything after the ? character.

$text = "http://example.com/application/view/viewleave.php?idleave=1";
$output = substr($text,0,strrpos($text,'?'));
echo $output;

edit: Like someone else said, if the string doesn’t contain ‘?’, then $output will be empty. So you could check for that first using strrpos()