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Home/ Questions/Q 671715
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T00:24:15+00:00 2026-05-14T00:24:15+00:00

I used a code: jQuery.fn.MyFunction = function(){ return this.each(function() { attributes = test; return

  • 0

I used a code:

jQuery.fn.MyFunction = function(){
return this.each(function() {
    attributes = "test";

    return attributes;
});}

But when I call

 var1 = $(this).MyFunction();alert(var1);

I got an [object], but not the “test”.

How to allow jquery plugin return a some value?

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  1. Editorial Team
    Editorial Team
    2026-05-14T00:24:16+00:00Added an answer on May 14, 2026 at 12:24 am

    jQuery plugins are generally designed to return a jQuery object so you can chain method calls:

    jQuery("test").method1().method2() ...
    

    If you want to return something else, use the following syntax:

    
    jQuery.fn.extend({
        myFunction: function( args ) {
                attributes = "test";
    
                return attributes;
        }
    });
    

    , or access it via its index using [].

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