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Asked: 2026-06-09T02:56:59+00:00

I want to extend the example called Object ListModel Example from Qt documentation (you

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I want to extend the example called “Object ListModel Example” from Qt documentation
(you can get it on http://qt-project.org/doc/qt-4.8/declarative-modelviews-objectlistmodel.html).

I am trying to add a simple GUI functionality: a menu item that changes the content
(i.e. name) of the first data item in the model. Something like this:

MenuItem {
  text: "Item 123"
  onClicked: {
    myModel.setProperty(0,"name","Item 123") //this gives me error
  }
}

I am able to create a menu in QML but I cannot find the correct way to make changes in the model.

Btw, what is a difference between setContextProperty and qmlRegisterType (only the first one is used in this example but many other examples include the second one).

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1 Answer

  1. Editorial Team

    That kind of model is really not suitable for modification. There is no way for the view to be notified of changes. A better option is to use a QAbstractItemModel: http://qt-project.org/doc/qt-4.8/declarative-modelviews-abstractitemmodel.html

    A simpler way to use a QAbstractItemModel is via QStandardItemModel: http://qt-project.org/doc/qt-4.8/qstandarditemmodel.html

    setContextProperty() adds a single named property to the context. qmlRegisterType() registers a QObject-derived type with the QML engine, allowing it to instantiate that type. For example, the QDeclarativeItem type is registered with the engine as “Item”, which is how the engine knows what to create when Item {} appears in QML code.

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