Question

I want to make my application as menu bar app and I made it already.
And also I want to track what application is running.

NSRunningApplication method returns all runnng applications.
But I want to detect the only application that is activated now. (with mouse click or command + tab…)
How can I find that?

I made code below :

- (void)applicationDidFinishLaunching:(NSNotification *)aNotification {
     [NSTimer scheduledTimerWithTimeInterval:0.1 target:self selector:@selector(performTimerBasedUpdate) userInfo:nil repeats:YES];
}

- (void)performTimerBasedUpdate {
     nowRunning = [NSRunningApplication currentApplication];
     nowRunningName = [nowRunning localizedName];
}

But, It returns the application name that I made (self).

• Answered

I finally find the answer : thank you i-blis.
I can get the activated application with filter.
I didn’t know about isActive property!

runningApplications_ = [[NSWorkspace sharedWorkspace] runningApplications];
nowRunning = [[runningApplications_ filteredArrayUsingPredicate:isActive] objectAtIndex:0];
bundleIdentifier_ = [nowRunning bundleIdentifier];
localizedName = [nowRunning localizedName];

Answer 1

You can easily find if an application is active with isActive. Then peek the localizedName or bundleIdentifier at your will. I am not really fluent in Objective-C but with Macruby syntax you’ll get it in the following way :

NSWorkspace.sharedWorkspace.runningApplications
    .select { |e| e.isActive == true }
    .map { |e| e.localizedName }

You may need to filter out your own application: I did not test how menu bar apps are handled in this regard.