Question

i want to open another program which is not in windows path.
below are code to open notepad which is in windows path.

Process process = Runtime.getRuntime().exec( "cmd.exe /C start notepad" ); 

and i want to open an exe file from the path below:

C:\Users\midi\Documents\Downloads\Compressed\ARToolKit-2.72.1-bin-win32\ARToolKit\bin 

please help me.
thanks in advance

Answer 1

Assuming the executable is called “Executable.exe” it should simply be

Process process = Runtime.getRuntime().exec("cmd.exe /C start C:\\Users\\midi\Documents\\Downloads\\Compressed\\ARToolKit-2.72.1-bin-win32\\ARToolKit\\bin\\Executable.exe" );

If it’s a wise decision to hardcode the absolute path is another question.