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Home/ Questions/Q 745595
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Editorial Team
  • 0
Editorial Team
Asked: May 14, 20262026-05-14T09:36:05+00:00 2026-05-14T09:36:05+00:00

I want to show some progress information of a server side procedure (which in

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I want to show some progress information of a server side procedure (which in fact is an ffmpeg re-encoding).
The best way I though of was to use two different $.ajax() calls on myscript like this:

1) when the form is submitted (which would trigger the re-encoding) one $.ajax() would start the re-encoding like this:

   $.ajax({  
    type: "GET",  
    url: "runffmpeg.php",  
    data: dataString,  
    success: function(data, textStatus, XMLHttpRequest) {  
            //clearInterval(repeat);
            location.reload(); 
        }});

2) Then, a second $.ajax() call would start watching the resulted file’s size in order to inform the visitor of the progress, like this:

    $.ajax({  
        type: "GET",  
        url: "checkprogress.php",  
        data: dataString,  
        success: function(data, textStatus, XMLHttpRequest) {                   
                $('#submitted').html(data);
            }
    });

Actually this call I should be made within an setInterval of an 1 second period in order to show the progression.

Of course this doesn’t work (or else why I should I posted it) and I can’t find any reference of having 2 ajax calls on the same time.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T09:36:06+00:00Added an answer on May 14, 2026 at 9:36 am

    It’s perfectly acceptable to have two ajax calls at the same time.
    I would however not use setInterval, as you might end up with multiple calls to checkprogress.php if it takes more than a second to return. You’re better off having the success method launch a new ajax request, perhaps after a timeout, eg:

    function checkProg(){
      $.ajax({  
          type: "GET",  
          url: "checkprogress.php",  
          data: dataString,  
          success: function(data, textStatus, XMLHttpRequest) {                   
                  $('#submitted').html(data);
                  if (/* not yet complete */) {
                    setTimeout(checkProg,500);
                  }
              }
      });
    }
    
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