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Home/ Questions/Q 8233199
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T18:03:15+00:00 2026-06-07T18:03:15+00:00

I want to understand how a sys_write on a scsi device works. Therefore I

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I want to understand how a sys_write on a scsi device works. Therefore I wrote a simple test program, and added in the issue function of the device driver some debug printk() to print the ata_queued_cmd->scsicmd->cmnd.

int main() {
    int w;
    char buffer[512] = "test string with 512 byte";

    // OPEN
    int fd = open("/dev/sdd", O_WRONLY | O_SYNC);

    // WRITE
    w = write(fd,buffer,sizeof(buffer));

    return 0;
}

In /var/log/messages I can see the following issued commands:

  scsicmd->cmnd
------------------------------
 0x28 | READ(10)
 0x2A | WRITE(10)
 0x35 | SYNCHRONIZE CACHE (10)

The 512 Byte I want to write should be the blocksize. This is how I get this value:

root$ blockdev --getsize /dev/sdd # returns size in sectors
488397168
root$ blockdev --getsize64 /dev/sdd # returns size in sectors
250059350016
root$ python -c "print 250059350016.0/488397168"
512.0

It’s very important for me, that the data is power-failure safe written. That’s the reason why I want to wait for the reuturn with O_SYNC. Now I have some questions:

  • Why is there a READ before the WRITE?
  • Does the SYNCHRONIZE CACHE guarantee me, if the data is in the internal cache of the drive? Or is there more I could do to have a secure write?

Thank you very much 🙂

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T18:03:16+00:00Added an answer on June 7, 2026 at 6:03 pm

    OK I figured it out now. They read it to load the data into an internal Kernel buffer, so when you have multiple writes/reads, the data is already buffered.

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