Question

I want to use the <?php bloginfo('stylesheet_directory'); ?> inside my wordpress loop to reference an image but unsure how to do this. My image code is as follows:

<?php
      if (is_category('Events')) {
        echo '<img src="http://localhost/mmj/wp-content/themes/child-theme/img/live-banner.jpg" class="live-holder-img" />';
      } else if (is_category('News')) {
       echo '<img src="http://localhost/mmj/wp-content/themes/child-theme/img/live-banner.jpg" class="live-holder-img" />';
      } else {
        echo '<img src="" class="default" />';
    } ?>

I would rather replace http://localhost/mmj/wp-content/themes/child-theme with <?php bloginfo('stylesheet_directory'); ?> but Im aware that I cant include <?php inside <?php so I was wondering how I could do this?

Answer 1

You can use like this :

echo '<img src="'.get_bloginfo('stylesheet_directory').'/img/live-banner.jpg" class="live-holder-img" />';

Full code :

<?php
      if (is_category('Events')) {
        echo '<img src="'.get_bloginfo('stylesheet_directory').'/img/live-banner.jpg" class="live-holder-img" />';
      } else if (is_category('News')) {
       echo '<img src="'.get_bloginfo('stylesheet_directory').'/img/live-banner.jpg" class="live-holder-img" />';
      } else {
        echo '<img src="" class="default" />';
    } ?>

In shortly,
I’m using get_bloginfo() instead of bloginfo() for getting stylesheet directory, not printing out. And then using it like this :

echo 'Some strings here ' . get_bloginfo() . ' another strings';