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Asked: 2026-05-15T20:23:20+00:00

I want to use XPath (in Java) to parse XML files. However these XML

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I want to use XPath (in Java) to parse XML files. However these XML files are only available on the web (downloading them all manually is not an option (of course they have to be “downloaded” in order to be processed).

So basically my question is how to do I take a URI object and convert it into a File object. Do I need to use SCP or something in between to download the file. Any code, tutorials or just general advice would be much appreciated.

I had tried this:

    URI uri = new URI("http://www.somefiles.com/myfile.xml");
    InputStream is = uri.toURL().openStream();
    File xmlDocument = new File(uri);

But this gave a URI scheme is not "file" error.

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1 Answer

  1. Editorial Team

    You can make it more complicated, but this could be as simple as opening a stream from a URL.

    InputStream in = remoteURI.toURL().openStream();

    Now this is not a File object as originally requested, but I’m guessing your XPath library can process a generic InputStream. If not you’ll have to save the InputStream above into a temp file and create a File object on that.

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