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Home/ Questions/Q 491795
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T02:02:51+00:00 2026-05-13T02:02:51+00:00

I want to XML-Serialize a complex type (class), that has a property of type

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I want to XML-Serialize a complex type (class), that has a property of type System.Drawing.Bitmap among others.

    /// <summary>
    /// Gets or sets the large icon, a 32x32 pixel image representing this face.
    /// </summary>
    /// <value>The large icon.</value>
    public Bitmap LargeIcon { get; set; }

I now have found out that serializing the Bitmap with the default XML serializer does not work, because it does not have a public parameterless constructor, which is mandatory with the default xml serializer.

I am aware of the following:

  • There exists a workaround, posted here: http://www.dotnetspider.com/resources/4759-XML-Serialization-C-Part-II-Images.aspx
    . However since this includes adding another property this seems to me a bit of a hack.
  • There is also a deep XML serializing project on sourceforge.

I rather would not like referencing another project nor extensively tweak my class to just allow xml serialization of those bitmaps.

Is there no way to keep that simple?

Many thanks, Marcel

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  1. Editorial Team
    Editorial Team
    2026-05-13T02:02:52+00:00Added an answer on May 13, 2026 at 2:02 am

    I would do something like:

    [XmlIgnore]
    public Bitmap LargeIcon { get; set; }
    
    [Browsable(false),EditorBrowsable(EditorBrowsableState.Never)]
    [XmlElement("LargeIcon")]
    public byte[] LargeIconSerialized
    {
        get { // serialize
            if (LargeIcon == null) return null;
            using (MemoryStream ms = new MemoryStream()) {
                LargeIcon.Save(ms, ImageFormat.Bmp);
                return ms.ToArray();
            }
        }
        set { // deserialize
            if (value == null) {
                LargeIcon = null;
            } else {
                using (MemoryStream ms = new MemoryStream(value)) {
                    LargeIcon = new Bitmap(ms);
                }
            }
        }
    }
    
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