Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8320541
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 8, 20262026-06-08T22:40:58+00:00 2026-06-08T22:40:58+00:00

I wanted to construct a small program in python, counting the probabilities of a

  • 0

I wanted to construct a small program in python, counting the probabilities of a random number being divisible by a number.

In C, i would create an array, with the numbers and loop through them, adding one to another array that would store the sum of these probabilities.

I tried to do that in python with the tuples, but i cannot change their value. So what is the easiest way to do this?

Here is the code:

primes = (2,3,5,7,11,13,17,19,23,29)
numbers =(0,0,0,0,0 ,0 ,0 ,0 ,0 ,0)

for number in range(2,10000):
    for div in primes:
        x = 0
        if(number % div == 0):
            numbers[x]  += 1
        x+=1



print(numbers)
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-08T22:40:59+00:00Added an answer on June 8, 2026 at 10:40 pm

    The probability of a random integer being divisible by an integer n is 1/n.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Context I have a very large number of small classes or structures . The
Assuming i got really really large list of random numbers in a text file
Hi i run Joomla site on htpp://www.deeptechtons.net and wanted to construct a membership based
Note: .toDataURL() and todataurl-png-js are NOT usable Say I wanted to construct an image
I wanted to create a little macro to simulate for(auto item : container) in
I ran into a small problem what i cant figure out. I would liked
If I wanted to badly enough, could I add additional LINQ constructs to LINQ-to-SQL
I have never written copy constructor, so in order to avoid pain i wanted
Wanted to know if there was a way one could query shelveset details from
Wanted to know if someone had a suggestion on code or maybe there's a

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.