Question

I wanted to get all strings inside a parentheses pair. for example, after applying regex on

"fun('xyz'); fun('abcd'); fun('abcd.ef') { temp('no'); " 

output should be

['xyz','abcd', 'abcd.ef'].

I tried many option but was not able to get desired result.
one option is
/fun\((.*?)\)/gi.exec("fun('xyz'); fun('abcd'); fun('abcd.ef')").

Answer 1

Store the regex in a variable, and run it in a loop…

var re = /fun\((.*?)\)/gi,
    string = "fun('xyz'); fun('abcd'); fun('abcd.ef')",
    matches = [],
    match;

while(match = re.exec(string))
    matches.push(match[1]);

Note that this only works for global regex. If you omit the g, you’ll have an infinite loop.

Also note that it’ll give an undesired result if there a ) between the quotation marks.