Question

I was reading the SO question about displaying integers as hex using C (without using %x, by using a custom function) and the first answer mentions using bitwise operators to achieve the goal.

But I can’t figure it out on my own. Can anyone tell me how this would be done?

Answer 1

I hope this makes it a little clear to you.

char *intToHex(unsigned input)
{
    char *output = malloc(sizeof(unsigned) * 2 + 3);
    strcpy(output, "0x00000000");

    static char HEX_ARRAY[] = "0123456789ABCDEF";
    //Initialization of 'converted' object

    // represents the end of the string.
    int index = 9;

    while (input > 0 ) 
    {
        output[index--] = HEX_ARRAY[(input & 0xF)];
        //Prepend (HEX_ARRAY[n & 0xF]) char to converted;
        input >>= 4;            
    }

    return output;
}