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Home/ Questions/Q 8308607
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T18:51:40+00:00 2026-06-08T18:51:40+00:00

I would like to ask question regarding pointers. I dont know what to do

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I would like to ask question regarding pointers. I dont know what to do here, I have a method in the main that is calling a method outside the main, and I need to use pointers.Basically this is the rough draft of it: Thanks!

 char *book[] = { "x", "y", "z",};
 int number[] = { 1, 2, 3};

 struct data{ char *bookname; int booknumber;};

 struct data *list[3];

  my_method(char *x, int y, int *z)
 {


   //creating a new struct 
   list[(*z)++] = (struct data*) malloc( sizeof(struct data) );

   //assigning arguments
   list[(*z)++]->bookname = x;
   list[(*z)++]->booknumber = y;

   (*z)++;
 }

 int main()
 {
   int nextValue = 0;

   my_method(book[nextValue], book[nextValue], &nextValue);

   int i;
   for(i = 0; i < 3; i++)
   {
     function(book[i], number[i]);

     printf("name: %c number: %d", list[i]->bookname, list[i]->booknumber);
   }
  }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T18:51:41+00:00Added an answer on June 8, 2026 at 6:51 pm

    It looks like you are passing the wrong arguments to your method. Try changing the following line:

    my_method(book[nextValue], number[nextValue], &nextValue);
    

    In addition, in your method you seem to be incrementing z four times, which I doubt is the behavior you want. You should only increment it once at the end, like the following:

    //creating a new struct 
    list[*z] = (struct data*) malloc( sizeof(struct data) );
    
    //assigning arguments
    list[*z]->bookname = x;
    list[*z]->booknumber = y;
    
    (*z)++;
    
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