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Home/ Questions/Q 5980431
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T21:47:59+00:00 2026-05-22T21:47:59+00:00

I would like to execute a method which can only be called once my

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I would like to execute a method which can only be called once my QApplication is displayed, i.e. when it has entered its main event loop exec_(). I’m new to Qt4 (using PyQt4): i was hoping to have a on_start()-like callback, but didn’t find one.
Do i need to create a thread or a timer? Or is there some callback included in the API already?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T21:48:00+00:00Added an answer on May 22, 2026 at 9:48 pm

    For now i have chosen to use QThread this way:

    class MyThread(QtCore.QThread):
        def run(self):
        ''' reinplemented from parent '''
            # make thread sleep to make sure
            # QApplication is running before doing something
            self.sleep(2)
            do_something()
    
    class MyWidget(QtGui.QWidget):
        def __init__(self, parent=None):
            QtGui.QWidget.__init__(self, parent)
            self.attr = 'foo'
            self.thread = MyThread(self)
            self.thread.start()
    
    def main():
        app = QtGui.QApplication(sys.argv)
        w = MyWidget()
        w.show()
        sys.exit(app.exec_())
    

    It works for my purpose because my thread in my (real) code actually looks for the application window in X display and will try doing so until it finds it. But otherwise that’s not an elegant way to solve the problem.
    It would be nicer if there was a signal emitted by QApplication when entering the event-loop. JAB proposed the Qt.ApplicationActivate but it doesn’t seem to be emitted by QApplication, and even if it was, because the MyWidget() is not instantiated as a child of QApplication, i wouldn’t know how to pass the signal from app to w

    I’ll wait for a better answer, if any, before accepting my answer as the chosen solution.

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