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Home/ Questions/Q 8201137
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T06:42:22+00:00 2026-06-07T06:42:22+00:00

I would like to know how to create view which also works even if

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I would like to know how to create view which also works even if the foreign key is NULL. For example we have table Person which has a primary key and two foreign keys:

  • IdPerson
  • FkName
  • FkSurname

Both foreign keys can be NULL. Now we also have two tables, table Name:

  • IdName
  • Name

And table Surname:

  • IdSurname
  • Surname

Now we create view to display name and surname for each Person:

CREATE VIEW `Database`.`ViewPerson` AS 
SELECT `N`.`Name`, `S`.`Surname`
FROM `Person` `P`, `Name` `N`, `Surname` `S`
WHERE (`P`.`FkName` = `N`.`IdName`) AND (`P`.`FkSurname` = `S`.`IdSurname`)

The problem is, if the foreign key FkSurname is NULL, than that row will not be displayed even though FkName is defined. I want that even if both foreign keys are NULL it still returns row where both columns are NULL. Now I know that I could solve it by adding in table Name and in table Surname row, that has NULL under Name/Surname and then in the FkName and FkSurname reference a row that has NULL values under those two columns. But I would still like to find out if there is a solution where foreign key is NULL and the row is returned.

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  1. Editorial Team
    Editorial Team
    2026-06-07T06:42:24+00:00Added an answer on June 7, 2026 at 6:42 am

    If I understand your question correctly, you want to get the corresponding values (even if null) for the Name and Surname fields in the Name and Surname table for each record in the Person table.

    This seems like a straightforward case where LEFT JOIN would work correctly. So, based on your query above, the SQL would be:

    CREATE VIEW Database.ViewPerson AS
    SELECT
      N.Name, S.Surname
    FROM Person P
      LEFT JOIN Name N ON N.IdName = P.FkName
      LEFT JOIN Surname S ON N.IdSurname = S.FkSurname;
    

    (sorry of the syntax isn’t 100% correct, I didn’t go through and create a test table to confirm it)

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