Question

$i=0;
while (db_data) {
$i++;
echo '<input type="checkbox" name="v['.$i.']" value="'.$url.'"';
if ($v[$i]) {
  echo ' checked';
  $s .= $url;
}
echo '/>';

}

I have the above array of checkboxes. It worked on my pc, but not on the server; it seems like the confusing part is on $v[$i].

$v is not defined, but sure used no where else. the problem is my checkbox selection never restored, and code never get into the if statement.

however, if i add the following, i can see the value. just the checkbox lost after the processing
$v=$_POST[‘v’];
while (list ($key,$val) = @each ($v)) {
$x .= ‘ 11*’.$key.’-‘.$val.’*22 ‘;
}

my goal is to preserve the checkbox checked on the form, and i need the $s elsewhere. any solution to replace $v[$i]?

Can anybody help me fix this? Thank you.

Answer 1

The issue seems to be $v = $_POST. If you are just doing that then your conditional statement would need to be

if ($v['v'][$i]) {
   ///Checkbox
}

or just do $v = $_POST[‘v’].

Sorry, ignore above as you did mention you did that part. See below.

Here is working code.

<form action="" method="post">
<?php
$v = $_POST['v'];
$i=0;
while ($i < 4) {
    $i++;
    $url = "test.com/".$i;
    echo '<input type="checkbox" name="v['.$i.']" value="'.$url.'"';
    if ($v[$i]) {  
        echo ' checked="checked"';  
        $s .= $url;
    }
    echo '/> '.$url.'<br />';
}
?>
<input type="submit" name="submit" value="submit" />
</form>

I left the code pretty much the same to show you where you went wrong, but you should be checking the $_POST variable for exploits before using. If I were doing this as well, I would use a for count, but it’s setup as a placeholder for your database code. Make sure that $url gets populated as well.

You could also do away with the $i variable like:

<?php
$v = $_POST['v'];
while (db_data) {
    echo '<input type="checkbox" name="v[]" value="'.$url.'"';
    if (is_array($v)) {
         if (in_array($url,$v)) {  
              echo ' checked="checked"';  
              $s .= $url;
         }
    }
    echo '/> '.$url.'<br />';
}
?>