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Editorial Team
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Asked: 2026-06-08T08:22:42+00:00

$i_id = $_GET[‘iiSL’]; require_once(‘../include/dbc.php’); $sql = SELECT invite_id FROM invite_requests WHERE invite_id = ‘$i_id’;

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$i_id = $_GET['iiSL'];   

require_once('../include/dbc.php');    

$sql = "SELECT invite_id FROM invite_requests WHERE invite_id = '$i_id'";
$result = mysql_query($sql);
if(mysql_num_rows($result == 1))
{
echo 'GOOD ID EXISTS';
//ECHO IS JUST TO TEST  
} 
else
{
echo 'BAD ID IS NOT IN DB';
//ECHO IS JUST TO TEST
}

Why is this not working? It’s driving me insane.

ERROR
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource

All spelling, grammar, syntax, and case is correct. URL is passing the $i_id variable. It echo’s out correctly.

What am I doing wrong?

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1 Answer

  1. Editorial Team

    There is a typo in the condition..try this..

    if(mysql_num_rows($result) == 1)

    You are passing result of $result == 1 to mysql_num_rows which expects a result resouce of mysql_query()..:)

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