Question

Iam doing a project in which i have to upload Image to the server using an URL.
But When i am uploading the file the file is corrupted in the server, when i open the file it is showing an error message, “file corrupted”. How can i overcome this problem.

Here is my code:

String lineEnd = "\r\n";
            String twoHyphens = "--";
            String boundary = "*****";

        try {
            // ------------------ CLIENT REQUEST

            Log.e("Upload", "Inside second Method");

            FileInputStream fileInputStream = new FileInputStream(new File(sel_img_name));

            // open a URL connection to the Servlet

            URL url = new URL(IpAddress+"ImageUpload/"+token+"/"+name_sel_image+"%7C"+extension);

            // Open a HTTP connection to the URL

            conn = (HttpURLConnection) url.openConnection();

            // Allow Inputs
            conn.setDoInput(true);

            // Allow Outputs
            conn.setDoOutput(true);

            // Don't use a cached copy.
            conn.setUseCaches(false);

            // Use a post method.
            conn.setRequestMethod("POST");

            conn.setRequestProperty("Connection", "Keep-Alive");

            conn.setRequestProperty("Content-Type",
                    "multipart/form-data;boundary=" + boundary);

            DataOutputStream dos = new DataOutputStream(conn.getOutputStream());

            dos.writeBytes(twoHyphens + boundary + lineEnd);
            dos.writeBytes("Content-Disposition: post-data; name=uploadedfile;filename="
                            + name_sel_image + "" + lineEnd);
            dos.writeBytes(lineEnd);

            //Log.e(Tag, "Headers are written");

            // create a buffer of maximum size

            int bytesAvailable = fileInputStream.available();
            int maxBufferSize = 1000;
            // int bufferSize = Math.min(bytesAvailable, maxBufferSize);
            byte[] buffer = new byte[bytesAvailable];

            // read file and write it into form...

            int bytesRead = fileInputStream.read(buffer, 0, bytesAvailable);

            while (bytesRead > 0) {
                dos.write(buffer, 0, bytesAvailable);
                bytesAvailable = fileInputStream.available();
                bytesAvailable = Math.min(bytesAvailable, maxBufferSize);
                bytesRead = fileInputStream.read(buffer, 0, bytesAvailable);
            }

            // send multipart form data necesssary after file data...

            dos.writeBytes(lineEnd);
            dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

            // close streams
            //Log.e(Tag, "File is written");
            fileInputStream.close();
            dos.flush();
            dos.close();

        } catch (MalformedURLException ex) {
            Log.e(Tag, "error: " + ex.getMessage(), ex);
        }

        catch (IOException ioe) {
            Log.e(Tag, "error: " + ioe.getMessage(), ioe);
        }
        try {
            BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream()));
            String line;
            while ((line = rd.readLine()) != null) {
                Log.i("Response", line);
            }
            rd.close();

        } catch (IOException ioex) {
            Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex);
        }

Answer 1

Don’t write the hyphens, boundary and lineEnd to see if your server supports it.
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

I had similar problem before and it turned out that the server was taking the hyphens, lineEnd as part of the data.