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Home/ Questions/Q 6476437
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T06:49:32+00:00 2026-05-25T06:49:32+00:00

I’d like to have a select box control display / hiding of sections in

  • 0

I’d like to have a select box control display / hiding of sections in a form

First, I added an .change event on the item, and this works if I actually change the item

$('#mySelect').change(
       function() {
            updateSections($(this));
       });

Then all I wanted is to have the .change event be called at least once, when the page is loaded

The only way I could think of is in $(document).ready which seems like a detached location

$(document).ready(function(){
    updateSections($('#mySelect'));

}

The main issue is that I don’t have the ID of the item from where I write the function (generated code)

So I would like to do something like this (conceptional code), and don’t know if there is any way to do it

$('#mySelect').change(
       function() {
            updateSections($(this));
       }).init(
       function() {
            updateSections($(this));
       });

.load() only works on a / img tags

Also from a design perspective, the onDraw of an item is a standard event in any UI framework, and having one event directly on the object, and one on the document looks weird to me

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T06:49:33+00:00Added an answer on May 25, 2026 at 6:49 am

    jQuery will allow you to just call the .change() method on load. You might do something like this:

    $(document).ready(function() {
        $('#mySelect').change(function() {
            updateSections($(this));
        });
    
        $('#mySelect').change();
    });
    

    You can probably put .change() after the first $('#mySelect') occurrence for brevity, but I wanted to be verbose; the $('#mySelect').change(); will fire the defined .change() event on the select box.

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