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Home/ Questions/Q 841273
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T05:45:58+00:00 2026-05-15T05:45:58+00:00

id Subject mark Year ————————- 1 Maths 32 2008 1 Science 40 2009 1

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id  Subject   mark   Year
-------------------------
1   Maths      32    2008
1   Science    40    2009
1   Science    45    2008
1   English    50    2009
1   English    60    2008

I am looking for a result like this:

id  Maths   Science   English
-----------------------------
1   32      40 & 45   50 & 60

Please advise. I am using MySQL.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T05:45:59+00:00Added an answer on May 15, 2026 at 5:45 am

    As @Mark suggested, GROUP_CONCAT() can give you the following result:

    SELECT   id, subject, GROUP_CONCAT(mark SEPARATOR ' & ') marks
    FROM     results 
    GROUP BY id, subject;
    +------+---------+---------+
    | id   | subject | marks   |
    +------+---------+---------+
    |    1 | English | 50 & 60 |
    |    1 | Maths   | 32      |
    |    1 | Science | 40 & 45 |
    +------+---------+---------+
    3 rows in set (0.00 sec)
    

    From this test case:

    CREATE TABLE results (id int, subject varchar(10), mark int);
    
    INSERT INTO results VALUES (1, 'Maths', 32);
    INSERT INTO results VALUES (1, 'Science', 40);
    INSERT INTO results VALUES (1, 'Science', 45);
    INSERT INTO results VALUES (1, 'English', 50);
    INSERT INTO results VALUES (1, 'English', 60);
    

    However another way to tackle the problem would be by using as sub query for each subject:

    SELECT    r.id,
              (SELECT   GROUP_CONCAT(r_eng.mark SEPARATOR ' & ')
               FROM     results r_eng
               WHERE    r_eng.subject = 'English' AND r_eng.id = r.id) English,
              (SELECT   GROUP_CONCAT(r_eng.mark SEPARATOR ' & ') 
               FROM     results r_eng
               WHERE    r_eng.subject = 'Maths' AND r_eng.id = r.id) Maths,
              (SELECT   GROUP_CONCAT(r_eng.mark SEPARATOR ' & ') 
               FROM     results r_eng
               WHERE    r_eng.subject = 'Science' AND r_eng.id = r.id) Science
    FROM      results r
    GROUP BY  r.id;
    

    Which will give the following result:

    +------+---------+-------+---------+
    | id   | English | Maths | Science |
    +------+---------+-------+---------+
    |    1 | 50 & 60 | 32    | 40 & 45 |
    +------+---------+-------+---------+
    1 row in set (0.01 sec)
    

    UPDATE:

    Further to the comments, it looks like you need to take the year field in consideration. Luckily the GROUP_CONCAT() function takes an ORDER BY clause which we can use. Let’s start from a new test case with the year field:

    CREATE TABLE results (id int, subject varchar(10), mark int, year int);
    
    INSERT INTO results VALUES (1, 'Maths', 32, 2008);
    INSERT INTO results VALUES (1, 'Science', 40, 2009);
    INSERT INTO results VALUES (1, 'Science', 45, 2008);
    INSERT INTO results VALUES (1, 'English', 50, 2009);
    INSERT INTO results VALUES (1, 'English', 60, 2008);
    
    SELECT * FROM results;
    +------+---------+------+------+
    | id   | subject | mark | year |
    +------+---------+------+------+
    |    1 | Maths   |   32 | 2008 |
    |    1 | Science |   40 | 2009 |
    |    1 | Science |   45 | 2008 |
    |    1 | English |   50 | 2009 |
    |    1 | English |   60 | 2008 |
    +------+---------+------+------+
    5 rows in set (0.00 sec)
    

    Then we would be able to use the GROUP_CONCAT() function with the ORDER BY clause as follows:

    SELECT   id, 
             subject, 
             GROUP_CONCAT(mark ORDER BY year SEPARATOR ' & ') marks, 
             GROUP_CONCAT(year ORDER BY year SEPARATOR ' & ') years
    FROM     results 
    GROUP BY id, subject;
    
    +------+---------+---------+-------------+
    | id   | subject | marks   | years       |
    +------+---------+---------+-------------+
    |    1 | English | 60 & 50 | 2008 & 2009 |
    |    1 | Maths   | 32      | 2008        |
    |    1 | Science | 45 & 40 | 2008 & 2009 |
    +------+---------+---------+-------------+
    3 rows in set (0.00 sec)
    

    Finally, to GROUP BY everything in one horizontal row, we can use the subquery technique that we used in the earlier example:

    SELECT    r.id,
              (SELECT  GROUP_CONCAT(r_eng.mark ORDER BY year SEPARATOR ' & ') 
               FROM    results r_eng
               WHERE   r_eng.subject = 'English' AND r_eng.id = r.id) English,
              (SELECT  GROUP_CONCAT(r_eng.year ORDER BY year SEPARATOR ' & ')
                FROM   results r_eng
                WHERE  r_eng.subject = 'English' AND r_eng.id = r.id) Years_English,
              (SELECT  GROUP_CONCAT(r_eng.mark ORDER BY year SEPARATOR ' & ')
               FROM    results r_eng
               WHERE   r_eng.subject = 'Maths' AND r_eng.id = r.id) Maths,
              (SELECT  GROUP_CONCAT(r_eng.year ORDER BY year SEPARATOR ' & ')
                FROM   results r_eng
                WHERE  r_eng.subject = 'Maths' AND r_eng.id = r.id) Years_Maths,
              (SELECT  GROUP_CONCAT(r_eng.mark ORDER BY year SEPARATOR ' & ')
               FROM    results r_eng
               WHERE   r_eng.subject = 'Science' AND r_eng.id = r.id) Science,
              (SELECT  GROUP_CONCAT(r_eng.year ORDER BY year SEPARATOR ' & ')
                FROM   results r_eng
                WHERE  r_eng.subject = 'Science' AND r_eng.id = r.id) Years_Science
    FROM      results r
    GROUP BY  r.id;
    

    Which will return the following:

    +----+---------+---------------+-------+-------------+---------+---------------+
    | id | English | Years_English | Maths | Years_Maths | Science | Years_Science |
    +----+---------+---------------+-------+-------------+---------+---------------+
    |  1 | 60 & 50 | 2008 & 2009   | 32    | 2008        | 45 & 40 | 2008 & 2009   |
    +----+---------+---------------+-------+-------------+---------+---------------+
    1 row in set (0.01 sec)
    

    If you wanted the marks and the years ordered in descending order, you could simply add the DESC keyword after each ORDER BY year.

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