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Editorial Team
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Asked: 2026-06-08T10:21:36+00:00

If I run this script: (Note: edited to reflect answer 1) #!/usr/bin/env zsh setopt

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If I run this script: (Note: edited to reflect answer 1)

#!/usr/bin/env zsh

setopt shwordsplit

if [[ -f $1 ]]
then
   echo "will compile $1"
else
  echo "ERROR: $1 NOT found"
  exit 1
fi

gcc_options="  -c -std=c99 -Wall -Wextra  "

echo "gcc_options: ${gcc_options}"

gcc " ${=gcc_options} " " ${=1} "

if [[ $? -eq 0 ]]
then
   echo "gcc compile worked"
else
   echo "error in gcc compile"
fi

gcc "${=gcc_options}" "${=1}"

if [[ $? -eq 0 ]]
then
   echo "gcc compile worked"
else
   echo "error in gcc compile"
fi

Both compiles fail.

Output is:

will compile my_file.c
gcc_options: -c -std=c99 -Wall -Wextra
gcc: error: : No such file or directory
gcc: error: : No such file or directory
gcc: error: my_file.c : No such file or directory
gcc: fatal error: no input files compilation terminated.
error in gcc compile
gcc: error: : No such file or directory
gcc: error: : No such file or directory
error in gcc compile

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1 Answer

  1. Editorial Team

    First change:

    gcc " $gcc_options $1"

    To:

    gcc "$gcc_options" "$1"

    If some of these variables contain multiple words, you may need to turn on shwordsplit (see here), which can also be done on a per variable basis (${=VAR}).

    gcc "${=gcc_options}" "${=1}"

    Update

    I made a mistake, you definitely don’t want quotes on $gcc_options, so it should probably be ${=gcc_options}. If you need to quote $1 depends if $1 contains spaces. So this should do:

    gcc ${=gcc_options} $1
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