Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8309889
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 8, 20262026-06-08T19:15:45+00:00 2026-06-08T19:15:45+00:00

I’m a huge fan of ES5’s Function.prototype.bind and currying arguments (basically creating default arguments

  • 0

I’m a huge fan of ES5’s Function.prototype.bind and currying arguments (basically creating default arguments for functions).

I was fooling around with that a bit, but I can’t for the life of me figure out my own construct anymore. This is my playground:

function hello( arg1, arg2 ) {
    console.log('hello()');
    console.log('"this" is: ', this);
    console.log('arguments: ', arguments);
}

var foo = Function.prototype.call.bind( hello,{what: 'dafuq'}, 2 );
foo( 42 );

The log output for this is as follows:

hello()
"this" is: Object{ what="dafuq" }
arguments: [2,42]

But I don’t understand how on earth the {what: 'dafuq'} object makes its way as a reference for the this within foo. As far as I understand it, we are creating a bound call to Function.prototype.call. Lets check the MDN synopsis for .bind() quickly:

fun.bind(thisArg[, arg1[, arg2[, ...]]])

so, thisArg for .call is the hello function, followed by the arguments list. Basically what happens is this

Function.prototype.call.call( hello, {what: 'dafuq'}, 2);

…uuhhh now my brain hurts a little. I think I have an idea now what happens, but please someone find nice solid words to explain it in detail.

  • how {what: 'dafuq'} becomes the this reference
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-08T19:15:46+00:00Added an answer on June 8, 2026 at 7:15 pm

    But I don’t understand how on earth the {what: 'dafuq'} object makes its way as a reference for the this within foo

    It’s because foo is effectively the call method with the hello function bound as the calling context, and that object bound as the first argument. The first argument of .call sets the calling context of its calling context. Since you’ve bound it, it means that object always be the calling context.


    Put it this way…

    You’ve bound the calling context of .call to hello.

    This is effectively the same as doing…

       hello.call();
    // or...
    // Function.prototype.call.call(hello);
    

    You’ve also bound the first argument of .call to {what: "dafuq"}, so this is effectively the same as doing…

    hello.call({what: "dafuq"});
    // or...
    // Function.prototype.call.call(hello, {what: "dafuq"});
    

    And finally, you’ve bound the second argument of .call to 2, so this is effectively the same as doing…

    hello.call({what: "dafuq"}, 2);
    // or...
    // Function.prototype.call.call(hello, {what: "dafuq"}, 2);
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a string like this: La Torre Eiffel paragonata all’Everest What PHP function
link Im having trouble converting the html entites into html characters, (&# 8217;) i
Basically, what I'm trying to create is a page of div tags, each has
I'm parsing an RSS feed that has an ’ in it. SimpleXML turns this
I need a function that will clean a strings' special characters. I do NOT
I want to construct a data frame in an Rcpp function, but when I
I have a .ini file as follows: [playlist] numberofentries=2 File1=http://87.230.82.17:80 Title1=(#1 - 365/1400) Example
That's pretty much it. I'm using Nokogiri to scrape a web page what has
I have just tried to save a simple *.rtf file with some websites and
I want to count how many characters a certain string has in PHP, but

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.