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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T08:38:04+00:00 2026-05-16T08:38:04+00:00

I’m basically trying to do this (pseudo code, not valid python): limit = 10

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I’m basically trying to do this (pseudo code, not valid python):

limit = 10
results = [xml_to_dict(artist) for artist in xml.findall('artist') while limit--]

So how could I code this in a concise and efficient way?
The XML file can contain anything between 0 and 50 artists, and I can’t control how many to get at a time, and AFAIK, there’s no XPATH expression to say something like “get me up to 10 nodes”.

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-16T08:38:04+00:00Added an answer on May 16, 2026 at 8:38 am

    Assuming that xml is an ElementTree object, the findall() method returns a list, so just slice that list:

    limit = 10
    limited_artists = xml.findall('artist')[:limit]
    results = [xml_to_dict(artist) for artist in limited_artists]
    
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