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Home/ Questions/Q 8380517
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T16:28:42+00:00 2026-06-09T16:28:42+00:00

I’m building a database for a small bookshop with a PHP web interface. For

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I’m building a database for a small bookshop with a PHP web interface. For this problem I want to display all records in the ‘products’ table (prod_core) without those that have a value in the products field ‘barcode’ equal to the ‘description’field in the ‘sales’ table (inc_core).

I actually managed to get this working for the first ‘sales’ mutation, but whenever I add a second record to the ‘sales’ table, the query doesn’t work any more. (except for the first record added). This is my SQL code:

SELECT prod_core.prodID, prod_core.title, prod_core.location, prod_core.genre,
       prod_core.price, prod_core.barcode
FROM   prod_core
WHERE  prod_core.barcode NOT IN (
         SELECT `description` 
         FROM inc_core
         GROUP BY prod_core.prodID)

I suppose it has something to do with SQL not looping (it stops searching the table for records that match the requirements) but I’m not sure. I would very much appreciate any help!

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  1. Editorial Team
    Editorial Team
    2026-06-09T16:28:43+00:00Added an answer on June 9, 2026 at 4:28 pm

    I would suggest a LEFT JOIN instead of a NOT IN:

    SELECT
        prod_core.prodID, 
        prod_core.title, 
        prod_core.location, 
        prod_core.genre, 
        prod_core.price, 
        prod_core.barcode
    FROM 
        prod_core 
        LEFT JOIN inc_core ON inc_core.`description` = prod_core.barcode
    WHERE
        inc_core.`description` IS NULL
    

    Also, since none of the columns in your SELECT statement are part of an aggregate function, I removed the GROUP BY and replaced it with DISTINCT… however, I don’t see why this table should include duplicates.

    EDIT: I misread your query and though that the group by was on the outer query, and not on the sub-query… +1 to the other answers that caught this.

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