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Home/ Questions/Q 1094495
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T23:58:49+00:00 2026-05-16T23:58:49+00:00

I’m currently implementing a copy constructor for a Linked List class. When I create

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I’m currently implementing a copy constructor for a Linked List class. When I create a new instance of the class with another Linked List as a parameter, the constructor is being called for the object I’m passing as the parameter. This is leaving me confused beyond belief. Here is the section necessary to understand what’s going on in the main method:

int main()
{
   LinkedList ll;
   LinkedList ll2(ll);
}

So, instead of calling the copy constructor for ll2, the copy constructor for ll is being called. I’ve confirmed that the size of ll is correctly 3 before I attempt to copy ll into a new LinkedList, namely ll2. After the copy though, both have the same size, greater than 3, but even more weird, the copy constructor of ll is being called, not that of ll2. Since I’m using VC++, I’ve stepped through the program to confirm this.

Here is the copy constructor for the LinkedList class:

LinkedList::LinkedList(const LinkedList & other)        
{
   LLNode *otherCurNode = other.GetFirst();
   if (otherCurNode != NULL)
   {
      front = new LLNode(otherCurNode->GetValue(), NULL, NULL);
      back = front;
   }
   else
   {
      front = NULL;
      back = NULL;
   }
   LLNode *curNode = front;
   while (otherCurNode != NULL)
   {
      Insert(otherCurNode->GetValue(), curNode);
      curNode = curNode->GetNext();
      otherCurNode = otherCurNode->GetNext();
      back = curNode;
   }
   numNodes = other.GetSize();
}   

My apologies if this ends up being a simple problem – I’m fairly new to C++. Any help will be greatly appreciated!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T23:58:49+00:00Added an answer on May 16, 2026 at 11:58 pm
    LinkedList ll = LinkedList();
    

    This creates a linked list instance, and this instance is then copy constructed. This looks like a Java or C#-ism. It is actually equivalent to:

    LinkedList ll(LinkedList());
    

    To create an empty linked list, simply write:

    LinkedList ll;
    

    This will implicitly call the default constructor.

    Also, make sure that you do have a default constructor which properly initializes the linked list to empty. If you don’t have one then the list’s variables will end up with whatever garbage values are on the stack.

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