I’m currently working on a proprietary shopping cart system and was having a few problems with getting products out with the correct pricing.
Basically my table structure is as follows:
Products table: (Only relevant columns are represented)
----------------------------------------------------
productid | product | descr | disporder| list_price|
----------------------------------------------------
1 name desc 1 0.00
2 name desc 4 0.00
3 name desc 2 2.45
Pricing table:
----------------------------------------
priceid | productid | price | variantid|
----------------------------------------
1 1 13.91 1
2 2 54.25 4
3 2 47.23 2
Variants Table:
-------------------------------
variantid | productid | active|
-------------------------------
1 1 Y
2 2 Y
3 2 Y
So, each product can have – and in most cases does have – multiple variants. My current SQL query I have managed to create thus far is:
SELECT
products.productid, product, descr, p.price, i.image_path
FROM
products
LEFT JOIN
pricing AS p
ON
p.variantid = (SELECT variantid FROM variants
WHERE productid = products.productid LIMIT 1)
LEFT JOIN
images_T AS i
ON
i.id = products.productid
GROUP BY
products.productid
ORDER BY
products.disporder
However, my problem arises when a product does not have a variant. If a product does not have a variant associated with it, the price will be in the list_price column of the products table. How would I go about performing a check to see if a product does indeed have a variant. If not, it should effectively bypass the variants table and get the pricing from list_price within the products table.
Yes, CASE is an option, or COALESCE:
Just join both prices and when the first is NULL the other will be selected.