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Home/ Questions/Q 8303483
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T17:33:21+00:00 2026-06-08T17:33:21+00:00

I’m having a problem with the sharedObject flush method. Is it possible to not

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I’m having a problem with the sharedObject flush method. Is it possible to not flush the new data when the swf is closed? My savegame function is the only function that calls the flush method and it also determines which array goes where in the sharedObject data.

parentMC.sharedObject.data.moveSpdUpgrade = parentMC.upgrades.tempMoveSpdUpgrade;
parentMC.sharedObject.flush();

However, when I modify the tempMoveSpdUpgrade array, it also saves the new data in the sharedObject even if the flush hasn’t been called yet.

tempMoveSpdUpgrade[0][2] = 1;
trace(parentMC.sharedObject.data.moveSpdUpgrade);

This trace shows that the data has changed but I don’t understand since the flush hasn’t been called and the swf hasn’t been closed. I’m wondering why the modifications made in the array automatically changes the sharedObject data.

Thank you for the help.

Edit:

public function saveGame(){  
    parentMC.sharedObject.data.money = parentMC.money;  
    parentMC.sharedObject.data.moveSpdUpgrade = parentMC.upgrades.tempMoveSpdUpgrade;  
    parentMC.sharedObject.flush();  
}

Like I stated in the comments with hackattack, the money is the correct data when I don’t save but the moveSpdUpgrade array is modified either way.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T17:33:24+00:00Added an answer on June 8, 2026 at 5:33 pm

    I think you are running into a bit confusing thing about arrays.
    What is happening never saves any data by another function or has something to do with the rest of your code.

    Simple the method how you try to copy the array of that Sharedobject doesnt create two seperate Obejcts. Instead you are always working live on the sharedObject-array.

    package
    {
      import flash.display.Sprite;
    
      public class arraytester extends Sprite
      {
    
        private var a:Array = new Array(1,2,3,4,5);
        private var b:Array = new Array("a","b","c","d","e","f");
    
        public function arraytester()
        {
    
        // Both arrays are different Objects
            trace(a); // 1,2,3,4,5
            trace (b); //a,b,c,d,e,f
    
        // Both arrays are pointing to the same Object
            a= b;
            trace(a); //a,b,c,d,e,f
            trace (b); //a,b,c,d,e,f
    
            b[1] = 2;
            trace(a); //a,2,c,d,e,f
            trace (b); //a,2,c,d,e,f
    
        // a is a copy of b while becoming a seperate Object
            a = b.concat();
            b[0]= 1;
            trace(a); //a,2,c,d,e,f
            trace (b); //1,2,c,d,e,f
        }
      }
    }
    
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