Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8299627
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 8, 20262026-06-08T16:13:17+00:00 2026-06-08T16:13:17+00:00

I’m in the process of moving some Mysql queries over to Postgresql and I

  • 0

I’m in the process of moving some Mysql queries over to Postgresql and I ran across this one that doesn’t work.

select (tons of stuff)
from trip_publication 

left join trip_collection AS "tc" on
tc.id = tp.collection_id

left join 
            trip_author ta1, (dies here)
            trip_person tp1,
            trip_institution tai1,
            trip_location tail1,
            trip_rank tr1
    ON
            tp.id = ta1.publication_id 
            AND tp1.id = ta1.person_id 
            AND ta1.order = 1 
            AND tai1.id = ta1.institution_id 
            AND tail1.id = tai1.location_id 
            AND ta1.rank_id = tr1.id

The query seems to be dying on the “trip_author ta1” line, where I marked it above. The actual error message is:

   syntax error at or near ","
   LINE 77:   (trip_author ta1, trip_person tp1, ... 

I went through the docs, and it seems to be correct. What exactly am I doing wrong here? Any feedback would be much appreciated.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-08T16:13:19+00:00Added an answer on June 8, 2026 at 4:13 pm

    I don’t know postgres, but in regular SQL you would need to a series of LEFT JOIN statements rather than your comma syntax. You seemed to have started this then stopped after the first two.

    Something like:

    SELECT * FROM
    table1 
    LEFT JOIN table2 ON match1
    LEFT JOIN table3 ON match2
    WHERE otherFilters
    

    The alternative is the older SQL syntax of:

    SELECT cols
    FROM table1, table2, table3
    WHERE match AND match2 AND otherFilters
    

    There’s a couple of other smaller errors in your SQL, like the fact you forgot your tp alias on your first table, and have tried including a where clause (ta1.order = 1) as a joining constraint.

    I think this is what you are after:

    select (tons of stuff)
    from trip_publication tp 
    left join trip_collection AS "tc" on tc.id = tp.collection_id
    left join trip_author ta1 on ta1.publication_id  = tp.id
    left join trip_person tp1 on tp1.id = ta1.person_id 
    left join trip_institution tai1 on  tai1.id = ta1.institution_id 
    left join trip_location tail1 on tail1.id = tai1.location_id 
    left join trip_rank tr1 on tr1.id = ta1.rank_id
    where ta1.order = 1
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I'm parsing an RSS feed that has an ’ in it. SimpleXML turns this
For some reason, after submitting a string like this Jack’s Spindle from a text
I have a string like this: La Torre Eiffel paragonata all’Everest What PHP function
I know there's a lot of other questions out there that deal with this
link Im having trouble converting the html entites into html characters, (&# 8217;) i
That's pretty much it. I'm using Nokogiri to scrape a web page what has
I have just tried to save a simple *.rtf file with some websites and
this is what i have right now Drawing an RSS feed into the php,
I've got a string that has curly quotes in it. I'd like to replace
I am reading a book about Javascript and jQuery and using one of the

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.