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Home/ Questions/Q 8243127
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T21:24:27+00:00 2026-06-07T21:24:27+00:00

I’m just learning R and having a hard time wrapping my head around how

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I’m just learning R and having a hard time wrapping my head around how to extract elements from objects in a list. I’ve parsed a json file into R giving me list object. But I can’t figure out how, from there, to extract various json elements from the list. here’s a truncated look at how my data appears after parsing the json:

 > #Parse data into R objects#
 > list.Json= fromJSON(,final.name, method = "C")
 > head(listJson,6)
[[1]]
[[1]]$contributors
NULL

[[1]]$favorited
[1] FALSE

...[truncating]...
[[5]]
[[5]]$contributors
NULL

[[5]]$favorited
[1] FALSE

I can figure out how to extract the favorites data for one of the objects in the list

> first.object=listJson[1]
> ff=first.object[[1]]$favorited
> ff
[1] FALSE

But I’m very confused about how to extract favorited for all objects in the list. I’ve looked into sappily, is that the correct approach? Do I need to put the above code into a for…next loop?

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  1. Editorial Team
    Editorial Team
    2026-06-07T21:24:29+00:00Added an answer on June 7, 2026 at 9:24 pm

    sapply is going to apply some function to every element in your list. In your case, you want to access each element in a (nested) list. sapply is certainly capable of this. For instance, if you want to access the first child of every element in your list:

    sapply(listJson, "[[", 1)
    

    Or if you wanted to access the item named “favorited”, you could use:

    sapply(listJson, "[[", "favorited")
    

    Note that the [ operator will take a subset of the list you’re working with. So when you access myList[1], you still have a list, it’s just of length 1. However, if you reference myList[[1]], you’ll get the contents of the first space in your list (which may or may not be another list). Thus, you’ll use the [[ operator in sapply, because you want to get down to the contents of the list.

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