Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8180787
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 7, 20262026-06-07T00:18:22+00:00 2026-06-07T00:18:22+00:00

I’m learning OCaml, and this is my first typed language, so try to be

  • 0

I’m learning OCaml, and this is my first typed language, so try to be patient with me:

For practice, I’m trying to define a function “divides?” which inputs two ints and outputs a boolean describing whether ‘int a’ divides evenly into ‘int b’. In my first attempt, I wrote something like this:

let divides? a b =
if a mod b = 0 then true
else false;; 

which gave the type error:

if a mod b = 0 then true
  ^
Error: This expression has type 'a option
       but an expression was expected of type int

So then I tried to turn it around and I did this:

let divides? a b =
 match a mod b with
  0 -> true
 |x -> false;;

which didn’t help much:
Characters 26-27
match a mod b with
^
Error: This expression has type 'a option
but an expression was expected of type int

Then I tried this:

let divides? (a : int) (b : int) =
 match a mod b with
 0 -> true
|x -> false;;

which elicited this:
Characters 14-15:
let divides? (a : int) (b : int) =
^
Error: This pattern matches values of type int
but a pattern was expected which matches values of type ‘a option.

I’m very confused and frustrated regarding the type system in general right now. (My first language was Scheme, this is my second.) Any help explaining where I’m going wrong and suggestions on how to fix it is much appreciated.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-07T00:18:25+00:00Added an answer on June 7, 2026 at 12:18 am

    The issue is that you can’t use the question mark character ? in a variable/function name in OCaml. It’s actually parsing your function declaration like this:

    let divides ?a b =
       if a mod b = 0 then true
       else false
    

    Note that the question mark is actually affecting the type of a, rather than being part of the name of the function.

    This means a is an optional parameter, so it gets assigned the type 'a option for some 'a.

    Try removing the question mark from the name.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a string like this: La Torre Eiffel paragonata all’Everest What PHP function
I am trying to understand how to use SyndicationItem to display feed which is
I'm parsing an RSS feed that has an ’ in it. SimpleXML turns this
link Im having trouble converting the html entites into html characters, (&# 8217;) i
For some reason, after submitting a string like this Jack’s Spindle from a text
I used javascript for loading a picture on my website depending on which small
Basically, what I'm trying to create is a page of div tags, each has
this is what i have right now Drawing an RSS feed into the php,
I have this code to decode numeric html entities to the UTF8 equivalent character.
I am trying to render a haml file in a javascript response like so:

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.