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Home/ Questions/Q 8331097
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T02:18:58+00:00 2026-06-09T02:18:58+00:00

I’m learning Python from an online tutorial. My problem is that when I run

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I’m learning Python from an online tutorial. My problem is that when I run the script, no matter what I input the response I get is the if go == “kitchen”…

def go_to():
    go = raw_input("Go to? ")

    if go == Kitchen or breakfast:
         print "You rumble down stairs and into the kitchen. Your mom has left some microwaved waffles on the table for you. Your big boy step sits by the counter."
    elif go == "back to bed" or "back to sleep" or bed or sleep:
        print "You hit snooze and roll over."
    elif go == "bathroom" or "toilet" or "potty" or "pee" or "poop" or "take a sh*t" or "take a dump" or "drop a load":
        print "You make a stop at the head first."
        go_to()
    else:
        print "That is not a command I understand."
        go_to()
go_to()
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T02:19:00+00:00Added an answer on June 9, 2026 at 2:19 am

    As Ignacio says, you need a new tutorial.

    The expression go == Kitchen or breakfast will be true if either of the subexpressions go == Kitchen or breakfast evaluate to True. This will happen if go evaluates to the same object as Kitchen, or their type defines an __eq__ method which defines equality for them, or it will be the case if breakfast is an object that is not None.

    The way to check if a variable contains a value in a list is:

    if go in (Kitchen, breakfast):
       # do something
    

    Note also that your code doesn’t show where the variables Kitchen and breakfast are defined, and your indentation is incorrect.

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