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Home/ Questions/Q 8296881
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T15:11:44+00:00 2026-06-08T15:11:44+00:00

I’m making a simple batch game, and I’m trying to find out how to

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I’m making a simple batch game, and I’m trying to find out how to use the value of a variable with an unknown name. Example:
I dont know the name or the value of the var1 variable, because it is automatically generated at an earlier point in the game.
The only thing I know is the 3rd line: set var3=var2.
I need my game to use the value of “var1” in an if statement like shown in the last line.
How would I do this?

set var1=5
set var2=var1
set var3=var2
if ??? EQU something something...
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  1. Editorial Team
    Editorial Team
    2026-06-08T15:11:47+00:00Added an answer on June 8, 2026 at 3:11 pm

    It took a few edits, but I finally came up with a truly bullet proof option (method 5).

    In method 5, if var3 is replaced by a variable name that contains " then you will have to escape some quotes. But if you are sophisticated enough to put a quote in a variable name then you already know how to do that 🙂

    @echo off
    setlocal
    
    set var1=5
    set var2=var1
    set var3=var2
    
    ::method 1 - Without using delayed expansion. (this is relatively slow and unsafe)
    ::           the initial expansion uses 1 % and no CALL
    ::           the 2nd expansion uses CALL and 2 %%
    ::           the 3rd expansion uses CALL and 4 %%%%
    ::           each additional expansion would require another CALL and doubled percents
    call call set "test=%%%%%%%var3%%%%%%%
    if "%test%"=="5" echo Method 1 works: Value of "unknown var"=%test%
    
    ::The remaining methods use delayed expansion. They are safer and faster.
    setlocal enableDelayedExpansion
    
    ::method 2 - Using normal and delayed expansion and a temp variable.
    ::           Almost always works, but can fail in rare cases where variable
    ::           name contains "
    set "test=!%var3%!"
    if "!%test%!"=="5" echo Method 2 works: Value of "unknown var"=!%test%!
    
    ::method 3 - Using normal and delayed expansion without using any temp variable.
    ::           This works for sensible variable names, but fails if name contains
    ::           * or ?. Also can fail if variable name contains "
    for %%A in ("!%var3%!") do if "!%%~A!"=="5" echo Method 3 works: Value of "unknown var"=!%%~A!
    
    ::method 4 - Using normal and delayed expansion without using any temp variable.
    ::           This almost always works, but can fail in rare cases where variable
    ::           name contains "
    for /f "eol==delims=" %%A in ("!%var3%!") do if "!%%A!"=="5" echo Method 4 works: Value of "unknown var"=!%%A!
    
    ::method 5 - Using delayed expansion without using any temp variable.
    ::           This always works!
    for /f "eol==delims=" %%A in ("!var3!") do for /f "eol==delims=" %%B in ("!%%A!") do if "!%%B!"=="5" echo Method 5 works: Value of "unknown var"=!%%B!
    
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