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Asked: 2026-06-08T15:26:07+00:00

I’m new in django and I’m reading a tutorial and it have an example

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I’m new in django and I’m reading a tutorial and it have an example but I think is a old Django version and now I’m using Django 1.4

views.py


 from django.http import HttpResponse
import datetime

def current_datetime(request):
    now = datetime.datetime.now()
    html = "<html><body>It is now %s.</body></html>" % now
    return HttpResponse(html)

def hours_ahead(request, offset):
    offset = int(offset)
    dt = datetime.datetime.now() + datetime.timedelta(hours=offset)
    html = "<html><body>In %s hour(s), it will be %s.</body></html>" % (offset, dt)
    return HttpResponse(html)

and the urls.py file

from django.conf.urls.defaults import *
from mysite.views import current_datetime, hours_ahead

urlpatterns = patterns('',
    (r'^time/$', current_datetime),
    (r'^time/plus/\d{1,2}/$', hours_ahead),


)
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1 Answer

  1. Editorial Team

    Your URL pattern is missing parenthesis to show that you want to capture the offset from the URL. Try changing it to the following:

    (r'^time/plus/(\d{1,2})/$', hours_ahead),

    Often, people prefer to use named groups in their URL patterns. In your case, the URL pattern would change to:

    (r'^time/plus/(?P<offset>\d{1,2})/$', hours_ahead),
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