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Home/ Questions/Q 8186939
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T02:23:39+00:00 2026-06-07T02:23:39+00:00

I’m new to Socket and I try to code an Server and Client on

  • 0

I’m new to Socketand I try to code an Server and Client on the same application just to see how it work.

Code:

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    ((Button)this.findViewById(R.id.bouton1)).setOnClickListener(this);

}


public void onClick(View v) {
    TCPServer server = new TCPServer();
    TCPClient client = new TCPClient();
    server.start();
    client.start();     
}

public class TCPServer extends Thread {
    @Override public void run() {

        try {

            ServerSocket s = new ServerSocket(8080,0,InetAddress.getLocalHost());
            Socket cli = s.accept();

            byte[] b = new byte[512];
            int n;

            InputStream is = cli.getInputStream();
            while((n=is.read(b))>0){
                Log.d("TCPServer",new String(b));
                if(new String(b).contains("\r\n\r\n"))break;
                b = new byte[512];
            }

            OutputStream os = cli.getOutputStream();
            os.write("Hello".getBytes());

        } catch (Exception e) { 
            e.printStackTrace();
        } 



    }
}
public class TCPClient extends Thread {     
    @Override public void run() {

        try {
            Socket s = new Socket(InetAddress.getLocalHost().getHostAddress(),8080);
            //Socket s = new Socket("www.google.com",80);                               
            //Log.i("",s.getLocalAddress().getHostAddress());

            byte[] b = new byte[512];
            int n;

            if (s.isConnected()) {

                OutputStream os = s.getOutputStream();
                os.write("Hi How are you \r\n\r\n".getBytes());

                InputStream is = s.getInputStream();
                while((n=is.read(b))>0){
                    Log.d("TCPClient",new String(b));
                    b = new byte[512];
                }

            }

            s.close();

        } catch (Exception e) { 
            e.printStackTrace();
        } 


    }
}

The code work fine but just for the first time I click my button.
the error is java.net.BindException: Address already in use .

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T02:23:41+00:00Added an answer on June 7, 2026 at 2:23 am

    If it works the first time, but not after that it sounds like you aren’t closing your socket correctly before your program exits.

    You can check to see if it’s still open by running

    netstat
    

    pending your not on a windows machine. I’m sure they have something similar.

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